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Holding Brake and Motor Torque Requirements
By Wilfred Voss, The effect of a holding brake on motor torque
requirements is usually minimal in a regular rotary or linear horizontal motion
application and is therefore not necessarily recommended. However, the torque
and power reduction can be quite dramatic in case of vertical linear
applications. The main purpose of a holding brake is to relief the motor from
maintaining the holding torque during standstill periods in a vertical linear
motion application. The use of a holding brake can save energy, not only due to
the application of the brake during standstill, but also due to smaller motor
size requirements. The downside of using a holding brake, however, is that it adds inertia to the motor load, therefore increasing torque and power requirements during acceleration and deceleration. Some criteria to use a holding brake could be:
The final decision to apply a holding brake should only
be based on calculating the torque requirements peak/intermittent as well as
RMS torque - of all possible motor/brake combinations and then select the motor
according to the lowest torque requirements. This is, of course, a time consuming
and tedious process, but yet again a good example where motor sizing programs
are a great help. Example 1: Linear Horizontal Application without holding
brake
Picture 1: Leadscrew Application Picture 1 shows a linear leadscrew
application with no holding brake and we assume the following parameters: Leadscrew Inertia 0.00004158 in-lb-s2 The duty cycle is set to: Total Duty Cycle Time 2 sec Note that we (initially) chose a mounting angle of zero
degrees to make this a linear horizontal application. We also added some
constant torque which is represented by the friction torque at the leadscrews input shaft. The resulting torque requirements in reference to the
duty cycle will look as follows:
Note: The above shown torque requirements do not include the
motors inertia. The graphs were created by the VisualSizer-Professional motor
sizing software. Notice that the required torque during acceleration and
deceleration remains very close to the constant torque represented by the
friction torque of the leadscrew. During acceleration
the added torque results from the leadscrews
inertia, since torque equals inertia times
acceleration. The same is true for the deceleration phase,
however, in this case the torque is reduced. The important part since we intend to add a brake
eventually is the dwell time. As can be seen in picture 2 the total torque of
the application will be zero during motor standstill, since this is a linear
horizontal application, i.e. the motor does not need to maintain a holding torque.
Ergo, in all consequence we do not need a holding brake. This picture will
change quite a bit when we change the mounting angle to 90 degrees, i.e. by
creating a vertical application. Example 2: Linear Horizontal Application with holding brake
First, however, lets add a holding brake to the
current linear horizontal application and observe the effects of the holding
torque. We are assuming a brake inertia of 0.004
in-lb-s2 which is for educational purposes - significantly higher
than the leadscrew inertia.
As picture 4 clearly demonstrates the effect of the
holding brakes inertia on the total torque, especially the intermittent
torque, is quite dramatic in this admittedly fabricated example. The point
really is that the use of a holding brake will increase the motor torque
requirements to a certain degree. In the next step lets set the leadscrew mounting angle to 90 % and make this a
vertical application, however, without applying the holding brake at
zero speed.
What happens here is that during acceleration the motor
has to move the load upwards against gravity -, while, during deceleration,
it has to move the load downwards with gravity. Common sense tells us that
the torque during deceleration, where moving the load is
In reference to picture 5 notice
the current torque during dwell time, i.e. at standstill. The torque during
dwell time is exactly 0.5 in-lb, i.e. the friction
torque applied at the leadscrews input shaft. The
motor needs to maintain this torque in order to keep the leadscrew
in the current position and to compensate for gravity forces.
Notice yet again the torque during dwell time in
picture 6, which is zero due to the applied holding brake. The maximum (intermittent) torque required from the
motor will be in both cases, with or without a holding brake applied, the same,
namely 0.94 in-lb. The main difference lies in the RMS torque, which is
used to determine the motors rated torque, i.e. the torque it can maintain
constantly. The equation to calculate the RMS torque is as shown here:
However, as was stated at the beginning, it is
important to calculate the torque requirements peak/intermittent as well as
RMS torque - of all possible motor/brake combinations and then select the motor
according to the lowest torque requirements. |
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Excerpt from: A Comprehensible Guide To Servo Motor Sizing by Wilfred Voss Published by Copperhill Technologies Corpoation Source: http://www.VisualSizer.Com 2005 - 2007 Copperhill Technologies Corporation. All rights reserved. |